SSC JE Previous Year Question Papers with Solutions

 

Question: Determine the separation between the plates (in mm) of a parallel plate capacitor placed in air, when the area of the plates is 0.002 sq. meter, the voltage of the battery connected to this parallel plate capacitor is 4 V and the charge stored on the plates is 16 pC.

Answer:

We know that C = Q/V

or, C=(16*10^(-12)) / 4

or, C = 4*10^(-12)

Capacitance between two parallel plates is calculated as, C = €A/d

Where, € = 8.854*10^(-12)
A = Area of plate
d = Distance between plates

Now, d = €A/C

or, d = (8.854*10^(-12)*0.002) / (4*10^(-12))

or, d = 4.4 mm

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