Question: Determine the separation between the plates (in mm) of a parallel plate capacitor placed in air, when the area of the plates is 0.002 sq. meter, the voltage of the battery connected to this parallel plate capacitor is 4 V and the charge stored on the plates is 16 pC.
Answer:
We know that C = Q/V
or, C=(16*10^(-12)) / 4
or, C = 4*10^(-12)
Capacitance between two parallel plates is calculated as, C = €A/d
Where, € = 8.854*10^(-12)
A = Area of plate
d = Distance between plates
A = Area of plate
d = Distance between plates
Now, d = €A/C
or, d = (8.854*10^(-12)*0.002) / (4*10^(-12))
or, d = 4.4 mm
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